The Antechamber is a small room, which it is necessary to go through to have access to the King’s Chamber. It was supposed to have inside a mechanism devised to close permanently the entrance corridor to the King’s Chamber. As part of this closing mechanism, it could be find the existence of two huge granite stone slabs (usually called granite leaf), one laying over the other and supported at its ends by slots cut at the east and west walls of the Antechamber. It is believed that the Egyptians builders, using strong ropes, round wooden posts, and the support of these two slabs, descended three stone blocks in front of the entrance to the King’s Chamber.

The so-called «boss" is a projection found over the north’s side of the upper slab (see figure 125). The north sides of the slabs were placed about 20 inches from the north wall of the Antechamber, and about 41 inches above the Antechamber’s floor. The meaning, or purpose of this stone projection is unknown. However, its strange form has given motives for speculations and comments. The boss was carved out of the stone slab’s face and is actually about one inch thick. Its appearance is like that of a horseshoe, but raise at its center. Its base, at the wall’s face is wider than at its top surface. It is about 8 inches wide by 5 inches height at its base. The top surface is about 5 inches wide by 3 inches height. These given measurements are approximate due to its deterioration. Some investigators refer to this carving as a decoration, others, as a support to hold the ropes; some consider it as of no value or importance. However, some investigators believe that its form could be a clue to the geometric definition of the Great Pyramid’s design.

When I examined the shape of this carving, as shown in photographs and drawings, it appeared to me as a drawing derived from the geometric configuration I used for the Great Pyramid. I traced some additional lines to my configuration and scaled the design to the boss’s height, and the drawing came out to match that for the boss, in its form, and its size. Even if this was a coincidence, it represents a geometrical method that could be used to build a model of the boss. Besides, for me, it represented an additional support to my theory about the Great Pyramid’s design.



Figure 125

To delineate the drawing of the boss, I used the same geometric configuration I developed for the Great Pyramid. This is shown in figure 126. For the drawing configuration, the radius (R) of the circle is assumed equivalent to one.


Figure 126

Trace the line OO’ from the center of the circle, perpendicular to the line PQ. With point O as center and OO’ as its radius, trace the circumference of another circle. Establish point Q’ at the intersection of its circumference, with the upper section of the vertical diameter QK. Trace the lines P’Q’ and Q’N’ parallel to the lines PQ and QN, respectively.

Figure 127


Figure 128

Join points P and P’, P’ and N’ and N’ and N, as shown in figure 128. Figure 129 delineates the configuration of the front view of the boss.

Figure 130 illustrates how it looks when the draft lines are erased. This seems to have the same configuration as the boss.



Figure 129

Figure 130

To establish the appropriate scale, set the radius of the exterior circle to 4 inches, as shown for the base section of the boss drawing. Automatically, all the dimensions in the drawing will be set, and can be calculated. Note that the segment of the circumference of the outside circle, between point P and N in figure 129, corresponds to the outside arc circumference in figure 130, while the inside circumference between points P’ and N’, also in figure 129, corresponds to the inside arc circumference in figure 130. Since the figure has to be analyzed as three-dimensional, the lateral view of the drawing shown in figure 131, illustrates the difference between the base line of the boss and that of its surface, or its thickness, that should be 1.2 inches.

Figure 131

Exterior circumference:

R = 4' D = 8'

(The formulas used are from Chapter 11)

The dimension Q X is equal to D / f = 8 / f = 4.94'. (Can be assumed as 5 inches)

Interior circumference:

Ri = radius of the interior circle = R / f = 4 / f = 2.47'

Di = Diameter of the interior circle = 2.47' (2) = 4.94' (Can be assumed as 5 inches)

The dimension Q’ X’ is equal to Di / f = 4.94 / f = 3.06' (Let 3 inches)

Vertical Dimension QQ’ = 4.0 - 2.47 = 1.53'

If these results are compared with the dimensions measured and reported by Sir W. M. Flinders Petri [Ref. #43, The Pyramids and Temples of Gizeh, page 26, it will be found that they are substantially in accordance. (Petrie indicates that it projects 0.94 to 1.10 from the block, and its measurements are anything between 4.7 and 5.2 wide, and between 3.3 and 3.5 high on its outer face, and between 7.2 and 8.2 wide and 5.6 to 6.6 height at its base).

If the original boss had its shape as it has been assumed, the fact that it can be accurately traced with the geometrical configuration used for the Great Pyramid, in the appropriate scale, could show another reason for its existence. It could have been left as his trademark, and as a key to direct us to the Great Pyramid’s geometric solution!